You'll have to write
match="*[local-name()='page' and namespace-uri()=$param-namespace]"
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Dvir Ofek
Sent: 12 November 2002 14:53
To: XSL-List(_at_)lists(_dot_) mulberrytech. com (E-mail)
Subject: [xsl] Parameterizing a namespace
Hi
Can anyone give me a hint how can I pass a namespace as a
parameter to a transformation, and use it inside the
transformation? I mean something like:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:t1="$param_namespace">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name "param_namespace"></xsl:param>
<xsl:template match="/">
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template match="t1:page">
<xsl:copy>
<xsl:copy-of select="@*" />
<xsl:value-of select="text()"/>
<xsl:apply-templates select="*" />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Of course this isn't valid, I just need somthing that can do the job.
Cheers
Dvir Ofek
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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