Hi Juan,
With your > <xsl:param name="attr" select"'itemid|desc'"/>,
i assume that you want to select the attributes itemid "or" desc.
In which case, for the following code, you would get an output:
145
hammer
145
nails
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:param name="node-names" select="'itemid|desc'"/>
<xsl:template match="/">
<xsl:variable name="attr1" select="substring-before($node-names,'|')"/>
<xsl:variable name="attr2" select="substring-after($node-names,'|')"/>
<xsl:for-each select="//@*[name() = $attr1 or name() = $attr2]">
<xsl:value-of select="."/><br/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
HTH
Vasu
----- Original Message -----
From: "Juan Carlos Gonzalez" <jcgonz(_at_)yahoo(_dot_)com>
To: <XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, November 06, 2002 2:35 PM
Subject: [xsl] Outputting dynamically
Hi:
I want to pass the node attributes name as an
parameter to the XSLT file to transform a XML file.
For example:
<customer id="1">
<order id="122" >
<orderdet date="12/12/02">
<item itemid="145" desc="hammer" qty="2"/>
<item itemid="145" desc="nails" qty="6"/>
</orderdet>
</order>
</customer>
Then I would have in the XSLT file something like or
if someone can come with a better idea:
<xsl:param name="attr" select"'itemid|desc'"/>
and based on that I want to ouput only these
attributes being passed.
Any suggestions,
thanks.
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