My query is that of a basic one, but with trying to many times, i have
failed in getting my xml data churned out in descending order, rather than
ascending, which is the de facto standard.
My XML structure is as follows:
<archive>
<news>
<date> </date>
<article> </article>
<author> </author>
</news>
</archive>
The XSL i use as follows:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="archive/news">
<xsl:sort select="archive/news" order="descending">
<table width="100%" border="0">
<tr>
<td class="yell" align="left"><xsl:value-of select="date"/></td>
<tr>
<td align="center"><xsl:value-of select="article"/></td>
</tr>
<tr><td class="yell" align="right"><xsl:value-of
select="author"/></td></tr>
</tr>
<tr />
<tr />
<tr />
<tr />
<tr />
<tr />
<tr />
</table>
</xsl:sort>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
It simply doesnt work, i have tried changing the nodes, and also have tried
changing where to put the sort, i understand it has to be within the for-each.
if anyone can provide a solution to this problem, much appreciated
thanks in advance
Gill.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list