Hello all,
Here's the xml:
<?xml version="1.0"?>
<bill>
<Services type="smtp" name="generic"
xmlns:src="http://xml.apache.org/xindice/Query"; src:col="/db/data/jobs/smtp"
src:key="2"/>
</bill>
the xsl:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:value-of select="//Services/@key"/>
</xsl:template>
</xsl:stylesheet>
and Saxon 6.5.2 and msxsl come up with nothing.
C:\projects\temp>msxsl test.xml test.xsl
■< ? x m l v e r s i o n = " 1 . 0 " e n c o d i n g = " U T F -
1 6 " ? >
C:\projects\temp>saxon test.xml test.xsl
<?xml version="1.0" encoding="utf-8"?>
If I substitute @src:key, then I get an error for an
undeclared namespace.
Dmitri's XPath visualiser finds the node just fine
using the @src:key syntax, but not using the @key
syntax.
How can I select the value of the src:key attribute
correctly?
Thanks!
Vic
_________________________________________________________________
Protect your PC - get McAfee.com VirusScan Online
http://clinic.mcafee.com/clinic/ibuy/campaign.asp?cid=3963
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list