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Re: xsl filter problem

2002-12-26 04:44:29
Hi Yuval,

When choosing "all cities" - the result is an empty table instead of 
the list of all cities with the customers names.
I tried to giva the param "city" a diect value of "*" or " '*' " and 
it still didn't work.
How can I pass a value to this param which will act like : <xsl:for-
each select="customers/customer[city=*]"> ??


Use:

customers/customer[city=$city or $city = '*']


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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