Hélder Sousa wrote:
<xsl:element name="input">
<xsl:attribute name="type">hidden</xsl:attribute>
<xsl:attribute name="name">todayDate</xsl:attribute>
<xsl:attribute name="value">????????</xsl:attribute>
</xsl:element>
The question is: how I put the actual date in "????????"?
100% portable way:
Put <xsl:param name="dateval"/> at the top of your stylesheet
(just before the first template)
and pass $dateval as an external parameter when you invoke the
XSLT processor. (see your XSLT processor's API documentation for
how to do this)
Is there any function in xsl that returns the actual date?
If your XSLT processor implements the EXSLT extension functions, yes.
See http://exslt.org/date/index.html, particularly date:date-time().
Note that there is even an implementation for MSXML (though you have
to embed it in your stylesheet).
<!--
xsl:import must be the first thing after xsl:stylesheet.
You need to get date.msxsl.xsl from
http://exslt.org/date/functions/date-time/date.msxsl.xsl
-->
<xsl:import href="date.msxsl.xsl"/>
<xsl:param name="dateval"/>
...
<xsl:template ...>
...
<input type="hidden" name="todayDate">
<xsl:attribute name="value">
<xsl:choose>
<xsl:when test="function-available('date:date-time')"
xmlns:date="http://exslt.org/dates-and-times";>
<xsl:value-of select="date:date-time()"/>
</xsl:when>
<xsl:when test="$dateval">
<xsl:value-of select="$dateval"/>
</xsl:when>
<xsl:otherwise>unknown</xsl:otherwise>
</xsl:choose>
</xsl:attribute>
</input>
...
</xsl:template>
Mike
--
Mike J. Brown | http://skew.org/~mike/resume/
Denver, CO, USA | http://skew.org/xml/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list