Use the doctype-system and doctype-public attributes of xsl:output,
don't try to generate the DOCTYPE declaration by hand.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Sorin Marti
Sent: 05 December 2002 08:28
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How to give out XML-Tags?
Hi all,
I'd like to make a Transformation with XSL and want to get a
docBook-Source out of it.
For that reason I need to give out something like
<!DOCTYPE Book PUBLIC "-//OASIS//DTD DocBook V4.1//EN"
"/usr/share/sgml/docbook_4/docbook.dtd">
<book id="How-to" lang="de">
I tried to put that in <xsl:text>, but that doesen't work.
Choosing "xml" as output-method is also no solution.
How do I do that, any advice?
Thanks for your help
Sorin
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