RE: & replacemnt?

Thanks for your answer, yes you are right about the source, it is wrongly 
encoded. Actualy, I have a source file in html containing these escaped 
sequences in the correct form (&#8217; in this case) but when I use xerces to 
create the XML document using the html as a source, the serializer gives me 
these double escaped sequences. Maybe it is because it is reading the 
characters one by one so when it sees the & character it translates it to &amp; 
then the following characters are put as is. Here is the java source code to 
generate the XML file (only the concerned method):

        protected void create(Document xmldoc){
                FileOutputStream fos = null;
                try{
                        // Write To File 
                        fos = new FileOutputStream(filename);
                        // XERCES 1 or 2 additionnal classes.
                        OutputFormat of = new 
OutputFormat("xml",OUTPUT_FORMAT,false);
                        of.setIndent(1);
                        of.setIndenting(true);
                        
                        XMLSerializer serializer = new XMLSerializer(fos,of);
                        
                        // As a DOM Serializer
                        serializer.asDOMSerializer();
                        serializer.serialize( xmldoc.getDocumentElement() );
                        
                        fos.close();

                } catch(Exception ex){
                        ex.printStackTrace();
                        System.out.println("Error:" + ex.getClass().getName() 
+":"+ ex.getMessage());

                } finally {
                                try{ fos.close();} catch(Exception 
ex){System.out.println("Can't close XML file outputstream");}
                }

        }

I guess that this code is responsible for the doule escaping.
I would be thankful for any help.
regards
Camille

-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk]
Sent: lundi 2 décembre 2002 18:15
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] &amp; replacemnt?

I have a source xml file containing data as:
<html>
  <b>Gamme de vitrages d&amp;#8217;allčges opacifiés </b>

_why_ is your source like that. &amp;#8217; is the XML syntax for the
7 characters & # 8 2 1 7 ; 
is there any reason that your source does not look like

<html>
  <b>Gamme de vitrages d&#8217;allčges opacifiés </b>

which is what you intended, I think.

If you must use the replace template  then you eant to replace 7
characters by 1, so that is

<xsl:param name="from" select="'&amp;#8217;'"/>
<xsl:param name="to" select="'&#8217;'"/>

Note you are _not_ trying to replace &amp; by &.

However it would be much better to fix your source files.

David

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RE: &amp; replacemnt?

RE: & replacemnt?