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Re: Transforming XML to HTML Table

2003-01-29 05:59:56
Nick Foster wrote:

but I only got the value of the first sample in all columns.  Is there a
way of looping through the $columntitles/labels and selecting the sample
where the label matches  in the current row?

Try
<xsl:for-each select="$columntitles">
        <TD>                                                      
                <xsl:value-of 
select="$samples[label=current()/label]/displayval"/>
        </TD>
</xsl:for-each>

But what's order? You've got "sample 1" in first row and "Sample 1" in the second one. Is this a typo?

--
Oleg Tkachenko
eXperanto team
Multiconn Technologies, Israel


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