Wendell,
That would return a number with all zeros stripped. I think what the
original poster wanted is something which would strip the zeros preceding
the no.
try this,
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";>
<xsl:template match="/">
<xsl:call-template name="stripzeros">
<xsl:with-param name="amount" select="//value"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="stripzeros">
<xsl:param name="amount"/>
<xsl:number value="$amount"></xsl:number>
</xsl:template>
</xsl:stylesheet>
Hope this helps.
Regards
Sudhakar
-----Original Message-----
From: Wendell Piez [mailto:wapiez(_at_)mulberrytech(_dot_)com]
Sent: Friday, January 24, 2003 4:19 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Removing leading zeros
Nischal,
Try the XPath function number($string) in your XSLT and see if it does what
you want. Since it turns any XPath object into a number, the leading zeros
won't appear.
If you need your number to be a string again (and you need to force it: for
most purposes it's unnecessary since XSLT will make the number a string
when it's passed and a string argument is required), try
string(number($string)). You won't get your leading zeros back.
Cheers,
Wendell
At 06:58 PM 1/24/2003, you wrote:
Hi All
I have a Java function which removes leading zeros
from a given string value and returns me the number.
Eg.
000125000 -- 125000
0012300 -- 12300
01234 -- 1234
public static String removeLeadingZeros(String str)
{
if (str == null)
{
return null;
}
char[] chars = str.toCharArray();
int index = 0;
for (; index < str.length(); index++)
{
if (chars[index] != '0')
{
break;
}
}
return (index == 0) ? str : str.substring(index);
}
Can someone help me build something like this in XSL.
I dont mean you to write for the script, but atleast
help me in taking thru what I have to do to get to
this.
Appreciate your time.
Thanks
Nischal
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