Hi David,
so how do you solve this problem?
Is the exsl:node-set solution the better one (respect to computation
time and memory consumption) ?
Regards,
--------------------------------
Marco Guazzone
Software Engineer
Kerbero S.r.L. - Gruppo TC
Viale Forlanini, 36
Garbagnate M.se (MI)
20024 - Italy
mail: marco(_dot_)guazzone(_at_)kerbero(_dot_)com
www: http://www.kerbero.com
Tel. +39 02 99514.247
Fax. +39 02 99514.399
--------------------------------
On Wed, 22 Jan 2003, David Carlisle wrote:
select="$sections/section[(_at_)group=1]/item[(_at_)id=1][$pos]"/>
the $pos item node that is a child of section[(_at_)group=1]
and has @id=1.
Since you have uniue ids within each section, if $pos is 1
you should get the same as
select="$sections/section[(_at_)group=1]/item[(_at_)id=1]"/>
but id pos is any number other than 1 you should get nothing as
there is only one item in each step satisfying [(_at_)id=1] so position() is
always equal to 1.
David
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