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Re: Finding the path from the filename

2003-01-20 13:01:28
This is a FAQ and has been answered several times on this list:

FXSL is ideally suited for such tasks. See for example:

http://sources.redhat.com/ml/xsl-list/2002-03/msg00399.html



=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL



"Thomas V. Nielsen" <thomas(_at_)integrator(_dot_)dk> wrote in message
news:0B777195ADF44B438161E97E6FB2A29D062EBE(_at_)mail(_dot_)xml(_dot_)local(_dot_)(_dot_)(_dot_)
In a XSLT I receive a parameter with a full path and file name, like;

C:\Data\Test\File.xml

I have tried fumbling with substring and substring-before, but with
no
luck.

What I need is the full path without the file name, like
C:\Data\Test\

Sometimes parameter looks like this

..\Test\File.xml

And also here I need to find the path, like ..\Test\

Any suggestions in how to use the substring with some iteration?

/Thomas

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