Ho Dimitri,
i tried to do it with msxml3 and 4
<?xml version="1.0" encoding="ISO-8859-1" ?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<root>
<test>xpath</test>
</root>
and
<xsl:stylesheet version='1.0'
xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>
<xsl:output method="text" />
..... (nothing changed)
<xsl:value-of select="$theResult"/>
and get as result
ÿþ
Never mind, which xsml-source i use, i get the same.
What i do wrong ?
Thanks,
Hans Braumüller
"S Woodside" <sbwoodside(_at_)yahoo(_dot_)com> wrote in message
news:1D578741-27F8-11D7-AD3E-000393414368(_at_)yahoo(_dot_)com(_dot_)(_dot_)(_dot_)
Gah! It's huge!
Seriously it looks like this will generate a string that, when
assigned
to a variable, and selected upon, will act as the correct XPath. Is
that right?
Yes, actually this snippet processes a nodeset of nodes and generates a
set of strings (XPath expressions) for each of them. You can simplify
it a bit to work only on a single node (get rid of the outermost
xsl:for-each).
It has: <xsl:value-of select="msxsl:node-set($theResult)"/>
Does it require MSxml? Can I turn $theResult (which is a string,
right?) into an XPath expression I can use in a select statement,
without needing MSXML?
Actually, the xxx:node-set extension function is not required.
Just get rid of it and the msxsl namespace, too.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
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