Wow Outstanding. That was perfect. Man Im realy loving this XML stuff! One last
question is how can I test if the current page is a Parent page. For example if
I wanted to Bold all the Parents that have children .
Thanks so much. This has been a huge huge help.
john
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Zink, Juergen
Sent: Tuesday, January 14, 2003 4:33 AM
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: AW: [xsl] Selecting out groups for a menu
Importance: Low
Hello John,
<snip>
The first group contains all the pages that have no children and sorts
them
in order by there priority the following groups >list by first the parent group
as the title and then the childrens below and list them by priority.
Unfortunatly this is all >over my head. Im trying my best to learn the
tutorials and figure out how i can do this but I am very stuck on how to group
this like above. Thanks for any help or info you can give me -john
Select the children that have no children (first apply-templates) with sorting
Select the children that have children (second apply-templates) list by
priority (third apply-templates)
Assuming there will be ever Pages with no children.
<xsl:template match="/">
<xsl:apply-templates select="PageHierarchy/Page[not(Page)]">
<xsl:sort select="@priority" />
</xsl:apply-templates>
<xsl:apply-templates select="PageHierarchy/Page[Page]">
<xsl:sort select="@priority" />
</xsl:apply-templates>
</xsl:template>
<xsl:template match="Page">
<xsl:if test="not(parent::Page) and Page">
<xsl:text>--------space----</xsl:text>
<xsl:element name="br"/>
</xsl:if>
<xsl:value-of select="@actualname"/>
<xsl:element name="br"/>
<xsl:apply-templates select="Page">
<xsl:sort select="@priority" />
</xsl:apply-templates>
</xsl:template>
Kind regards,
Juergen Zink
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