Hi,
Would
<xsl:if test="parent::view and not(parent::view/following-sibling::view)">
be what you are after?
cheers
andrew
-----Original Message-----
From: jfi(_at_)propack-data(_dot_)com [mailto:jfi(_at_)propack-data(_dot_)com]
Sent: 08 January 2003 15:43
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] position() and last() problem
Hi List,
I´ve got a problem finding out whether a parent element is a
"last()" one.
I read the FAQ but it didn´t help.
My XML file has the following structure:
<views>
<view>
<stuff>...</stuff>
</view>
<view>
<stuff>...</stuff>
<view>
<stuff>...</stuff>
<view>
<stuff>...</stuff>
</view>
<view>
<stuff>...</stuff>
</view>
</view>
<view>
<stuff>...</stuff>
</view>
</view>
</views>
That means each <view>-element can contain an undefined
number of other
<view>s. What I want to know is whether the parent of a
<view> - if it is
also the view - is the last one.
I tried <xsl:if test="ancestor::con:view[1][position()]!=last()">, but
understanding more and more of XSLT I know that can´t work.
But I don´t
know yet what can.
All whitespace is stripped.
Thanks for your help!
Julia
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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