Hi Sam,
I would like to have navigation where each page number is
displayed:
1 2 3 4 5
How do I do that? Is the only solution to use recursion?
No, you could use iteration to generate the page numbers by selecting
every 50th item and using xsl:for-each to loop through them:
<xsl:for-each select="item[position() mod 50 = 1]">
<a href="page{position()}.html">
<xsl:value-of select="position()" />
</a>
<xsl:if test="position() != last()">
<xsl:text> </xsl:text>
</xsl:if>
</xsl:for-each>
Within the xsl:for-each, the position of each item is its position
amongst the set that you've selected rather than its absolute position
in the list of items.
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list