Yes.
XSLT documents must be well-formed XML.
What is it supposed to do?
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-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]On Behalf Of
Hubert Holtz
Sent: Saturday, January 04, 2003 2:53 PM
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] closing a template inside a table, forbidden?
Hy,
is this forbidden ?
-----CODE-----
<xsl:template match="article">
<table>
...
</table>
<!-- ************SECT1 PROCESSING CONTENT ************** -->
<table width="610" height="48" cellpadding="0"
cellspacing="0" border="0" id="sectBackground">
<xsl:apply-templates select="./title[(_at_)lang= $lang]"/>
<xsl:apply-templates select="sect1[(_at_)lang = $lang or
not(@lang)]"/>
</xsl:template>
<xsl:template match="article/sect1[(_at_)lang= $lang or
not(@lang)]">
<xsl:apply-templates/>
</table>
----CODE----
I get the following error:
The element type "table" must be terminated by the matching end-tag "".
description org.apache.cocoon.ProcessingException: Exception in
creating Transform Handler: org.xml.sax.SAXParseException: The
element type "table" must be terminated by the matching end-tag "".
And if it is forbidden, why?
Thanks.
Steve
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list