[Lorenzo De Tomasi ]
how can I obtain an ordered list like this
...
Rendering
list: 1
2
3
4
5
Your example document has the values in sorted order already, so there is no
need to sort them again in the XSLT. This stylesheet will do what you ask:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" encoding="UTF-8" />
<xsl:strip-space elements="*" />
<xsl:template match="/">
<table>
<xsl:apply-templates select="xml/element" />
</table>
</xsl:template>
<xsl:template match="xml/element">
<xsl:choose>
<xsl:when test="position() = 1">
<tr><td>list:</td><td><xsl:value-of select="." /></td></tr>
</xsl:when>
<xsl:otherwise>
<tr><td> </td><td><xsl:value-of select="." /></td></tr>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
If the document does not contain the elements in sorted order, you could change
this:
<xsl:apply-templates select="xml/element" />
to this:
<xsl:apply-templates select="xml/element">
<xsl:sort select="." data-type="number" />
</xsl:apply-templates>
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list