Why would you want to count them, simply recursively process the nodes with
xsl:apply-templates using a mode if you have to.
eg (untested code)
<xsl:template match="menu">
<xsl:apply-templates match="item">
</xsl:template>
<xsl:template match="item">
<!-- the leaf node -->
<xsl:param name="parent-route"/>
<xsl:value-of select="concat($parent-route,string(position()))"/>
</xsl:template>
<xsl:template match="item[item]">
<!-- not a leaf node -->
<xsl:param name="parent-route"/>
<xsl:apply-templates select="item">
<xsl:with-param name="parent-route"
select="concat($parent-route,string(position()),'.')"/>
</xsl:apply-templates>
</xsl:template>
HTH,
Ken Ross
Ph: +61 7 32359370
Mob: +61 (0)419 772299
Email: Ken(_dot_)Ross(_at_)iie(_dot_)qld(_dot_)gov(_dot_)au
-----Original Message-----
From: cknell(_at_)onebox(_dot_)com [mailto:cknell(_at_)onebox(_dot_)com]
Sent: Tuesday, 4 February 2003 8:22 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XPath question
Every time I think I have a good grasp on XPath, it slips between my fingers.
Consider the following XML:
<menu>
<item title="Vegetables">
<item title="tubers">
<item title="potatoes">
<item>Idaho</item>
<item>Maine</item>
<item>Russet</item>
<item>Yam</item>
</item>
</item>
</item>
<item title="Fruits">
<item title="Apples>
<item>Fuji</item>
<item>Granny Smith</item>
<item>Rome</item>
</item>
<item>Milk</item>
</menu>
I have an HTML application for which I must flatten out the hierachy of this
XML document, yet still maintain a link to the parent element for each child
element. To this end I have decided to number each element according to its
position in the hierarachy and use a "dot-delimitted" format for each element's
id (i.01.03.11). I have struggled in vain today to come up with an XPath
expression which would tell me how many elements are on the preceding-sibling
axis of the parent of a given node. Can anyone straighten me out on this?
Thanks.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
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