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RE: position() returns doubled result - what do i miss?

2003-03-31 01:25:40
It's been a couple of months since anyone asked this, so you can be
forgiven...

You are processing the whitespace text nodes in between the elements, as
well as the elements themselves. To process only the elements, use
<xsl:apply-templates select="*"/>

Then I noticed you had written:

<xsl:apply-templates match="root/item"/>

But <xsl:apply-templates> does not allow a "match" attribute, so any
conformant XSLT processor should have given you an error message. Which
processor are you using?

Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com 

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com 
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of 
jian
Sent: 31 March 2003 07:50
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] position() returns doubled result - what do i miss?


i have :

<?xml version="1.0" encoding="UTF-8" ?>
<root>
      <item>item1</item>
      <item>item2</item>
      <item>item3</item>
      <item>item4</item>
      <item>item5</item>
      <item>item6</item>
      <item>item7</item>
      <item>item8</item>
      <item>item9</item>
</root>



to which i apply:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">

<xsl:output method="html" version="4.01" encoding="UTF-8"/>

 <xsl:template match="/">
   <xsl:apply-templates match="root/item"/>
 </xsl:template>

 <xsl:template match="item">
   <xsl:value-of select="position()"/>
   <xsl:value-of select="."/>
 </xsl:template>

</xsl:stylesheet>


and for some reason i get :

      2item1
      4item2
      6item3
      8item4
      10item5
      12item6
      14item7
      16item8
      18item9

what do i miss?

jian

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