Hey Jarno,
I htink you helped to get me onto the right road...
thanks mate
Daniel.
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Von: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]Im Auftrag von
Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com
Gesendet: Freitag, 28. März 2003 09:05
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff: RE: [xsl] identifying elements by contents of an attribute
Hi,
I believe this is very easy, but I just can't figure out how to do it.
I need to identify elements according to the value of a
specific attribute.
The XML document looks like this:
<?xml version="1.0" encoding="ISO-8859-1"?>
<INPUT>
<VERSION Type="Key"> 1.0 </VERSION>
<HEADER Type="Block">
<DATE Type="Key"> 06.03.2003 </DATE>
<USER Type="Key"> D. Brauer </USER>
</HEADER>
</INPUT>
For different values of the attribute "Type" (i.e. "Block", "Key")
differnet templates should be applied. These have to access
the name and
contents of the matched element respectively.
Can anybody give me a hint on this?
<http://www.w3.org/TR/xslt> and <http://www.w3.org/TR/xpath> most
probably can. Anyhow, I didn't quite get what you were after, but
just write templates with predicates
<xsl:template match="*[(_at_)Type = 'Key']">
<xsl:value-of select="name()" />: <xsl:value-of select="." />
...
<xsl:template match="*[(_at_)Type = 'Block']">
<xsl:apply-templates select="*" />
...
An so forth.
Cheers,
Jarno - Skinny Puppy: VX Gas Attack
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