Hi Florian:
Brute force method:
<xsl:template match="order/column">
<xsl:apply-templates select="/root/group/*[local-name()=current()/@name"/>
</xsl:template>
Quicker and easier method:
<xsl:key name="fruits" match="group/*" use="local-name()"/>
<xsl:template match="order/column">
<xsl:apply-templates select="key('fruits',@name)"/>
</xsl:template>
Not so hard....
Cheers,
Wendell
At 12:07 PM 3/27/2003, you wrote:
i have a document xml doc like this:
<root>
<group>
<apple>bla</apple>
<orange>bla</orange>
</group>
<group>
<apple>bla</apple>
<orange>bla</orange>
</group>
<order>
<column name="orange" />
<column name="apple" />
</order>
</root>
i would like to do the following: im going though all the column nodes
and would like to access the group nodes where the column attribute name
and the group node name match up.
basically i can just not think of a way to do that in xpath.. anybody
got an tip? how can i say in xpath that it should get the node with
the name in @name and not just access the name attribute of a group
node..
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Wendell Piez
mailto:wapiez(_at_)mulberrytech(_dot_)com
Mulberry Technologies, Inc. http://www.mulberrytech.com
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Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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