RE: transforming to breaks


Thanks Jarno!


-----Original Message-----
From: Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com 
[mailto:Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com] 
Sent: Tuesday, March 25, 2003 10:34 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] transforming to breaks

I have a node like <nodeName>blah blah&#13;&#10;more blah 
blah</nodeName>.
I wish to transform this to html, using <BR></BR> for the carriage
return/linefeed combo.

How can I do this?


Recursive template, e.g.

template "changer"
  param "text"
  choose
    when contains($text, "&#xA;")
      value-of substring-before($text, "&#xA;")
      <BR></BR>
      call-template "changer>
        with-param "text" substring-after($text, "&#xA;")
    otherwise
      value-of $text

The XML parser changes &#13;&#10; sequences into single &#10;, so you just
need to change LINE FEED characters.

Cheers,

Jarno - Linnunradan käsikirja liftareille: Osa 14

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