Hi Mike, this template exclude all elements child of
XMI.content, and I don't want this.
In this example, I want exlcude only
Foundation.Core.ModelElement.name.
How can I do this?
<xsl:template match="XMI.content">
<xsl:copy>
<xsl:apply-templates
select="@*|node()[not
(self::Model_Management.Model/Foundation.Core.ModelElemen
t.name)]"/>
</xsl:copy>
<xsl:apply-templates
select="Model_Management.Model/Foundation.Core.ModelEleme
nt.name"/>
</xsl:template>
PS: if I want exclude ALL instances of an element (they
appears in anyplace of XMI.content), and copy them at
the
end, what I must do?
This is the third time today that we've suggested this:
Use the identity transform, as discussed in the XSLT sp
ec under Copying:
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
This will result in a recursive copy of all nodes.
Add to it a template that matches the nodes you want to
treat specially:
<xsl:template match="XMI.content">
<xsl:copy>
<xsl:apply-templates select="@*|node()[not
(self::foo)]"/>
</xsl:copy>
<xsl:apply-templates select="foo"/>
</xsl:template>
In this case, you're excluding the 'foo' element chilre
n of the 'XMI.content'
element from being processed until after the copy of th
e XMI.content element
is made.
Mike
--
Mike J. Brown | http://skew.org/~mike/resume/
Denver, CO, USA | http://skew.org/xml/
XSL-
List info and archive: http://www.mulberrytech.com/xsl/x
sl-list
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