I'm hoping there's a more elegant way to do it using a one-line
apply-templates or call-templates instead of three or more if statement
lines. I've been pretty successful in getting most of the conditional code
out of my templates. This is one of the areas I haven't spent much time
trying to figured out yet...
From: "Dimitre Novatchev" <dnovatchev(_at_)yahoo(_dot_)com>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Re: Identifying Existence of Attributes
Date: Sat, 15 Mar 2003 09:43:37 +0100
<balajeec(_at_)mastek(_dot_)com> wrote in message
news:551A143C7FC0F64FA508178F55A7E01902FE2412(_at_)ind-spz7exh002(_dot_)mastek(_dot_)com(_dot_)(_dot_)(_dot_)
> Hi ,
> I have an element by the name
> <Text>
> I want to check whether the current <Text> node has the attribute by the
name
> "indent"
> defined in it.
> How can i do it.??
>
Just test for @indent
e.g.:
<xsl:if test="@indent ">
<!-- do something -->
</xsl:if>
Translated in English the above means: "if the current node has an
attribute
named 'indent' do something".
The test does not depend on whether the current node is named "Text",
because you said this is already a known fact.
In case you want to check that both the current node is named "Text" and it
has an attribute named "indent", the XPath expression that returns the
truth
value of this fact is:
self::Text and @indent
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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