Craig Wehr wrote:
I am having a problem with xsl:if not working properly.
This is what I want to do:
if there is content in the "BlockBody" node in the XML file,
everything is output to the file.
if there is no content in the "BlockBody" node in the XML file,
the xsl skips the BlockBody output, yet outputs the <HR> and <A> link.
ex:
<xsl:template match="BlockBody">
<xsl:if test="BlockBody!=''">
<p><xsl:text>Policy</xsl:text></p>
<p><xsl:apply-templates/></p>
</xsl:if>
<hr></hr>
<p><a href="index.html" class="bodyLink">[Table of
Contents]</a></p>
</xsl:template>
I'm not sure if <xsl:if test="BlockBody!=''"> is valid.
can anyone help me make this work?
I think you want
<xsl:if test="string()">
If you say test="BlockBody!=''" you are asking whether there is
a child of the context node (BlockBody) called BlockBody,
whose string value is not ''.
Lars
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