You can have an xsl:choose inside the xsl:with-param element.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
email(_at_)magusdesigns(_dot_)com
Sent: 13 March 2003 05:17
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Variable Values for Params
Hello-
I am applying templates with a parameter. This parameter
should have a different
value depending on what part of my xsl:choose statement is
applied. In the xsl:when, I
want $count = 0, but in the xsl:otherwise, i want $count = 1.
How can I pull this off
considering variables cannot be redefined, and I can't have
an xsl:choose inside an
xsl:apply-templates tag?
Thanks-
Mac
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