Hi all,
I am having a problem with a template to pass over some unused tags without
printing them out to the responce OutputStream in html.
I have the following xsl sheet (Very simple) and when I do not include the
<xsl:template match="*" /> I get my output the way I want it, but with all
the remainder of the xml as text at the bottom of the screen. If I include
the match="*" template I get nothing at all.
Any pointers would be handy. (NOTE: All paths in templates are absolute)
Cheers
Simon
[CODE]
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="html"/>
<!-- template rule matching source /root/tables element -->
<xsl:template match="/root/tables">
<h1>Avaliable subsystems and signals</h1>
<table border="1" cellpadding="3">
<tbody>
<tr>
<th>Subsystem</th>
<th>Time Select (Not implemented)</th>
<th>Signal Select</th>
</tr>
<xsl:apply-templates select="/root/tables/table"/>
</tbody>
</table>
</xsl:template>
<xsl:template match="/root/tables/table">
<tr>
<td>
<b><xsl:value-of select="@name"/></b>
</td>
<td width="50" bgcolor="red">
<b><u>Time stamp not implemented yet!</u></b>
</td>
<td>
<xsl:for-each select="column">
<xsl:apply-templates
select="/root/tables/table/column"/>
</xsl:for-each>
</td>
</tr>
</xsl:template>
<xsl:template match="/root/tables/table/column">
<b>Click to select :</b><xsl:value-of select="."/><br/>
</xsl:template>
<!-- This is the line causing the problem -->
<xsl:template match="*" />
</xsl:stylesheet>
Institut fuer
Prozessdatenverarbeitung
und Elektronik,
Forschungszentrum Karlsruhe GmbH,
Postfach 3640,
D-76021 Karlsruhe,
Germany.
Tel: (+49)/7247 82-4042
E-mail : kelly(_at_)ipe(_dot_)fzk(_dot_)de
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list