Hello again
Thanks for the answer. I was think if there was a way of using ./ancestor::*
Something like this
<xsl:variable name="path" select="./ancestor::*"/>
<xsl:variable name="elements" select="document($doc)//*"/>
and then find THE element with the same ancestors.
<xsl:variable name="element" ...
Best regards
Johan Thoren
-----Original Message-----
From: Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com
[mailto:Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com]
Sent: den 28 april 2003 11:38
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Get specific elements
Hi,
I have an XML looking like
<AAA>
<BBB>
<CCC>
</CCC>
</BBB>
<CCC>
</CCC>
</AAA>
How can I specify to get the CCC with parent /AAA/BBB element
separated from the
CCC with parent /AAA/. Meaning getting an element depending
on all preceding
parents. I reckon this could be done recursively. But Im
stuck at the moment...
"/AAA/BBB/CCC" or "//CCC[parent::BBB]" or "//CCC[not(parent::AAA)]" or write
more specific template match patterns i.e. "AAA/BBB/CCC" and "AAA/CCC" etc.
Which is the best depends on what your stylesheet looks like, that is where you
want to "specify to get the CCC".
Cheers,
Jarno - Hocico: Spit as an offence(suicide commando remix)
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