Your code *is* passing a node as the argument - specifically, it is
passing an attribute node. To pass an element node, just use a path
expression that selects the element instead of the attribute -
<xsl:with-param name="label" select="comp/attribute[(_at_)name='country']"/>
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Andreas Schlegel
Sent: 25 April 2003 17:12
To: mulberrytech-xsl-list
Subject: [xsl] WITH-PARAM with node as argument?
Hi,
I would like to write a with-param statement with a node as
argument and
handle this node in a template. But I don't know if it is possible or
even what is the syntax. The following example is my current
code which
has to much arguments (IMHO). It would be great if I could
reduce it to
only 1 argument.
<xsl:call-template name="textfield">
<xsl:with-param name="label"
select="comp/attribute[(_at_)name='country']/@label"/>
<xsl:with-param name="name"
select="comp/attribute[(_at_)name='country']/@name"/>
<xsl:with-param name="size"
select="comp/attribute[(_at_)name='country']/@size"/>
<xsl:with-param name="value"
select="comp/attribute[(_at_)name='country']/@value"/>
</xsl:call-template>
<xsl:template name="textfield">
<xsl:param name="label"/>
<xsl:param name="name"/>
<xsl:param name="size"/>
<xsl:param name="value"/>
<tr>
<th align="left"><xsl:value-of select="$label"/></th>
<td align="left" colspan="1">
<xsl:element name="input">
<xsl:attribute name="type">text</xsl:attribute>
<xsl:attribute name="name"><xsl:value-of
select="$name"/></xsl:attribute>
<xsl:attribute name="size"><xsl:value-of
select="$size"/></xsl:attribute>
<xsl:attribute name="value"><xsl:value-of
select="$value"/></xsl:attribute>
</xsl:element>
</td>
</tr>
</xsl:template>
Greetings,
Andreas
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