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Re: xsl:if giving me "Invalid type" error

2003-04-15 13:15:50
James,

At 03:15 PM 4/15/2003, you wrote:
This . . .

<xsl:variable
  select="(div[1]|div0[1]|div1[1]|divGen[1])[1]"/>

. . . seems more on track.

Of course you and David are correct (me spacing out), and what I just wrote would be complete overkill.

Not that there haven't been times when I've had to do stuff like that....

Cheers,
Wendell


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Wendell Piez                            
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