Hi,Can somebody help me with the following issue: I want to replace my
blank rows with the values from the preceeding non-blank rows. A blank row
is a row containing all empty cells.
My xml is as follows:
<row>
<column name="firstname">K1</column>
<column name="lastname">L1</column
</row>
<row> --> Empty Row contains empty cells
<column name="firstname></column> --> These should be replaced by
<column name="lastname></column> --> "K1" and "L1" from prev. row.
</row>
<row> --> Empty row again.
<column name="firstname></column>
<column name="lastname></column>
</row>
....
here is my xslt file. It works for the first empty non-row. However, since
I always replaced it with row[$position-1] (i.e. immediate preceeding row),
if there were 2 blank rows together, the second blank row was not replaced
correctly because the preceeding row was still empty.
I have this for-loop. So, how can I save the non-blank row position?
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="xml"/>
<xsl:param name="fillCell" select="'N'"/>
<xsl:template match="/">
<Document>
<xsl:for-each select="Document/row">
<!-- To determine whether the row contains all empty cells. If so, STR
must be returned as '' --->
<xsl:variable name="STR">
<xsl:apply-templates select="column" mode="row"/>
</xsl:variable>
<xsl:choose>
<xsl:when test="$STR != ''">
<xsl:copy-of select="."/>
</xsl:when>
<xsl:when test="$STR = '' and position() > 0 and $fillCell = 'Y'">
<xsl:variable name="pos" select="position() -1"/>
<xsl:copy-of select="//Document/row[$pos]"/>
</xsl:when>
</xsl:choose>
</xsl:for-each>
</Document>
</xsl:template>
<xsl:template match="text()" mode="row">
<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
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