Hi,
Im having the following situation;
- A template which calls template 'Display' with
a node-set as parameter ...
<xsl:template match="/">
<xsl:call-template name="Display">
<xsl:with-param name="rows" select="//path/to/nodes"/>
</xsl:call-template>
</xsl:template>
... template Diplay kindly gets $rows, does some
further magic and is supposed to call template 'Display_ext'
with again $rows and an additional value ...
<xsl:template name="Display">
<xsl:param name="rows"/>
<xsl:variable name="item" select="some_value"/>
<xsl:if test="$rows">
<xsl:call-template name="Display_ext">
<xsl:with-param name="rows" select="$rows"/>
<xsl:with-param name="item" select="$item"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
... now, strangely, Display_ext is not able to
assign $rows[$item], even though
$rows is unchanged ...
<xsl:template name="Display_ext">
<xsl:param name="rows"/>
<xsl:param name="item"/>
<xsl:value-of select="$rows[$item]"/>
</xsl:template>
... the errormessage is as follows;
XPath error Invalid type in $images[1] ..
Does anyone has an idea on what could be the failure's
reason or on how one can pass a node-set as variable through multiple templates?
I appologize if this question falls into the
newbie-section ...
silvan
--
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list