Hi Johan,
I think the error message is clear. But according to
http://www.exslt.org/str/index.html
the concat(node-set) should work with EXSLT.
Why Im trying with concat is that I need the string as a variable
and not in the output.
You are trying to use the EXSLT extension function str:concat(), but
because you aren't using the prefix "str:" on your function call, you
are actually using the built-in function concat(). The built-in
function concat() concatenates the two-or-more strings that it is
passed as arguments. The extension function str:concat() from EXSLT
concatenates the values of the nodes in the node set that it is passed
as an argument.
You must declare the prefix for the extension function in the
<xsl:stylesheet> element:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:str="http://exslt.org/strings";
extension-element-prefixes="str">
...
</xsl:stylesheet>
and then call the function including the "str:" prefix:
<xsl:template match="*">
<xsl:variable name="allnodename"
select="str:concat(ancestor-or-self::*)"/>
...
</xsl:template>
Note that this will only work with processors that support
str:concat() (4XSLT and libxslt). Also note that the call
"str:concat(ancestor-or-self::*)" will *not* give you a string
consisting of the *names* of all the ancestors of the current node,
but rather their values. To do get their names, you should use the code:
<xsl:template match="*">
<xsl:variable name="allnodename">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="name()" />
</xsl:for-each>
</xsl:variable>
...
</xsl:template>
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list