USe this xsl
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<ROWSET>
<xsl:for-each select="html/body/h">
<ROW>
<HEADER>
<xsl:value-of select="."/>
</HEADER>
<BODY>
<xsl:value-of select="
following-sibling::*[generate-id(following-sibling::html/body/h[1])=
generate-id(current()/following-sibling::html/body/h[1])]"/>
</BODY>
</ROW>
</xsl:for-each>
</ROWSET>
</xsl:template>
</xsl:stylesheet>
sundar
-----Original Message-----
From: Smirnov, Anatoliy
[mailto:anatoliy(_dot_)smirnov(_at_)mail(_dot_)va(_dot_)gov]
Sent: Thursday, May 01, 2003 8:32 PM
To: 'XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: [xsl] how to get rid of tag names
Hello,
Sorry for such a dumb question but I am new here.
I need to get rid of tag names <p> and </p> in the result document.
<?xml version = '1.0'?>
<ROWSET>
<ROW>
<HEADER>
header
</HEADER>
<BODY>
<p>p line</p>
</BODY>
</ROW>
</ROWSET>
so instead of
<p>p line</p>
I just need to have
p line
I am getting this from this source
<html>
<body>
<h>header</h>
<p>p line</p>
</body>
</html>
running this xsl
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<ROWSET>
<xsl:for-each select="html/body/h">
<ROW>
<HEADER>
<xsl:value-of select="."/>
</HEADER>
<BODY>
<xsl:copy-of select="
following-sibling::*[generate-id(following-sibling::html/body/h[1])=
generate-id(current()/following-sibling::html/body/h[1])]"/>
</BODY>
</ROW>
</xsl:for-each>
</ROWSET>
</xsl:template>
</xsl:stylesheet>
Thank you.
Anatoliy Smirnov
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