RE: number continuation problem

 the second self::else should of course be an self::if (although it
 produces the same result on your test case)

and (either) one of the &gt; should be &gt;= otherwise if both branches
have the same number of nodes you'll skip over both of them.

David


Hi David,

Thanks for the great example, I've added the changes you mentioned.  There's 
one problem in that <else>'s shouldn’t count it's preceeding <if>'s nodes (they 
should both start with the same number).  Using the example below, you should 
see that the 3rd from last entry gets reported as a 7 when it should be 5.  

<root>
        <if>
                <node>(1)</node>
                <node>(2)</node>
        </if>
        <else>
                <node>(1)</node>
                <node>(2)</node>
                <node>(3)</node>
        </else>
        <if>
                <node>(4)</node>
        </if>
        <else>
                <node>(4)</node>
        </else>
        <if>
                <node>(5)</node>
                <node>(6)</node>
        </if>
        <else>
                <node>(5)</node>
        </else>
        <if>
                <node>(7)</node>
        </if>
        <else>
                <node>(7)</node>
        </else>
</root>

Now, if you make it handle nested if/else's within nodes that would be special 
:)


Heres the template with the modifications you've stated (apologies for not 
pretty printing it):

<xsl:template match="node">
.<xsl:value-of select="
1 +
count(preceding-sibling::node) +
count(../preceding-sibling::if[count(node)&gt;count(following-sibling::*[1][self::else]/node)]/node)
 +
count(../preceding-sibling::else[count(node)&gt;=count(preceding-sibling::*[1][self::if]/node)]/node)
"/>.<xsl:value-of select="."/>
</xsl:template>


cheers
andrew


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