Hi,
I have this element hierarchy
Source::
root
body
record1(*)
record2(*)
Destination::
root1
body1
record3(*)
record4(*)
Here occurence of record1 and record2 can occur any number of times.This
will be my source xml on which the transform is to be applied.Following is
the xsl
<xsl:template match="/" name="root">
<xsl:element name="root1">
<xsl:element name="body1">
<xsl:for-each select="/root/body/record1">
<xsl:element name="record3"><xsl:value-of
select="concat(.,'1')"/></xsl:element>
</xsl:for-each>
<xsl:for-each select="/root/body/record2">
<xsl:element name="record4"><xsl:value-of
select="concat(.,'2')"/></xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:element>
</xsl:template>
Only problem would be that i need the order of records to be same in
output
as in input and input of records can be in random order,viz
<record1><record1><record2><record1><record2><record1>.But with the two
for-loops this will break the sequence.
How can this be done.
Any help on this would be deeply appreciated.
Thanks,
Shadab
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