xsl-list
[Top] [All Lists]

Re: xpath question

2003-06-22 13:59:54

On Sonntag, Juni 22, 2003, at 10:37  Uhr, Mike Brown wrote:

florian wrote:
hi!

i unfortunately cant think of a xpath statement for this:


i want to get all the child nodes of my current node, which
have an node with the name 'bar' and where the content
of the node is 'apples'..

the tricky part now is that the name 'bar' and 'apples' is defined
in another node somewhere in the document.

*[*[local-name() = /someNode/@theAttributeWithTheValueBar] =
/fruits/roundOnes[1]]

doesnt really seem to work..

<xsl:variable name="barname" select="string(/someNode/@theAttributeWithTheValueBar)"/>
<xsl:variable name="fruitname" select="string(/fruits/roundOnes[1])"/>

then

*[local-name() = $barname and . = $fruitname]

You can do it without variables but this way it gives the processor
an opportunity to
 optimize.

thanks alot, mike!

im suing that statement in an for-each element.. so im wondering if there is anyway to return the parent of the bar node and not the bar note itself..


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



<Prev in Thread] Current Thread [Next in Thread>