I suspected as much. It's not two parents having the same child, it's
two parents having different children that share the same name.
This makes it a classic grouping problem, so go and read the Jeni
Tennison tutorial that's been cited twice this morning already.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Bita Jooooooon
Sent: 18 June 2003 08:50
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] How to find all parents having the same child?
Here an example:
<Quries>
<Query name="query1">
<Query name="query2">
<Table name="table1"/>
<Table name="table2"/>
<Query name="query3">
<Table name="table3"/>
</Query>
</Query>
</Query>
<Query name="query4">
<Table name="table1"/>
<Table name="table2"/>
<Table name="table3"/>
</Query>
</Queries>
Given that, I would like to extract all parents for
each leaf like the following:
table3: query4, query3
table1: query4, query1
query3: query2
query2: query1
An example from you on how to get that cross-reference
list would help me a lot.
regards,
bjoon
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