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Re: Current node position

2003-06-11 12:44:41
you could try putting the date in a variable

<variable name="dateList" select="./date" />
then do the position and count of $dateList

----- Original Message ----- 
From: "jwhitney" <jwhitney(_at_)unb(_dot_)ca>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, June 11, 2003 14:55
Subject: [xsl] Current node position


Hello,

I'm trying to generate html code for "Date 1 of 2", "Date 2 of 2", etc.,
from
XML as below:

<a>
   <b/>
   <c/>
   <date>text</date>
   <date>text again</date>
</a>

from within a template that matches "d".  The following stylesheet
fragment:

<xsl:template match="d">
  <xsl:value-of select="position()" />
  <xsl:text> of </xsl:text>
  <xsl:value-of select="count(../date)" />
</xsl:template>

produces "3 of 2" and "4 of 2".  Is there a way to restrict position() to
evaluate the <date> nodes only?  How else could it be done?

I'm new to XSLT, obviously.   Thanks in advance for any help with this.



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