RE: Adding a node in sequence

Thanx,

Do I need to 
include xsl:copy to pass across the newly created node?
Can I declare the variable x outside the template?
I like the method and the short hand way of creating the node     <yes
ID="{$x}"/>
Salud

  <xsl:template match="*[yes]">
<xsl:copy>
    <xsl:apply-templates select="yes[(_at_)ID &lt; $x]"/>
    <yes ID="{$x}"/>
    <xsl:apply-templates select="yes[(_at_)ID >= $x]"/>
</xsl:copy>
  </xsl:template>
  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>


-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Jarno(_dot_)Elovirta(_at_)nokia(_dot_)com
Sent: Monday, 2 June 2003 4:20 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Adding a node in sequence


Hi,

> Using xsl:copy I want to insert a date node in a date sequence. How 
> would u insert the node
>
>
>                       <yes ID="20030526">
>                       </yes>
> In the below sequence.
[snip]

How about

  <xsl:template match="*[yes]">
    <xsl:variable name="x" select="20030526"/>
    <xsl:apply-templates select="yes[(_at_)ID &lt; $x]"/>
    <yes ID="{$x}"/>
    <xsl:apply-templates select="yes[(_at_)ID >= $x]"/>
  </xsl:template>
  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>

Cheers,

Jarno - HMB: Everything

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 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list