Hi,
true, you cannot use a variable in the match pattern.
So you have to do either:
<xsl:template match="absent">
<xsl:if test="not(from = $vardate and ancestor::player/@pword = $varpword)">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:if>
</xsl:template>
or
<xsl:template match="absentia">
<xsl:copy>
<xsl:apply-templates select="@*|node()[not(from = $vardate and
ancestor::player(_at_)pword = $varpword)]"/>
</xsl:copy>
</xsl:template>
Regards,
Markus
__________________________
Markus Abt
Comet Computer GmbH
http://www.comet.de
----------
Von: John Reid
Gesendet: Mittwoch, 30. Juli 2003 23:50
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff: RE: [xsl] Deleting a node depending on contents of a
grandfather attribute and a child node
I understood that I could not use variables in a template match
statement such as
<xsl:template match="absent[ancestor::player/@pword=$varpword
and from=$vardate]"/>
Or am I missing something?
Salud
John
John Reid wrote:
i have tried a number of approaches but with various but not correct
results. I want to delete the absent node (and everything below it)
where $vardate = from and @pword $varpword.
..
<xsl:variable name="pword" select="ancestor::@pword"/>
Wont select anything, ever. Try
<xsl:variable name="pword" select="ancestor::player[1]/@pword"/>
or if the player node is always the grandfather
<xsl:variable name="pword" select="../../@pword"/>
<xsl:copy>
<xsl:apply-templates select="@*|node()[not($date1 = $vardate and
$pword = $varpword)]"/>
</xsl:copy>
This does not quite match your problem description ("I want to
delete the absent node"). The following template
<xsl:template match="absent[ancestor::player/@pword=$varpword
and from=$vardate]"/>
will make processing the nodes in questions a no-op (iow kill it),
other absent nodes are copied through by the other template.
J.Pietschmann
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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