RE: Using a reference in a sort

> Try <xsl:sort
select="document($filePeople)/people/person[(_at_)id=current()/person/@id]/@l
ast"
>   order="descending"/> instead
Thanks for your reply, but I'm sorry to report that that doesn't work
either.  The context of current() is still the node in the other XML
file.  The documentation I have says that current() is the same as ".",
which I tried and does not help, either.

More suggestions, please!

Jesse




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list