xsl-list
[Top] [All Lists]

RE: Sorting and re-ordering down a hierarchy

2003-07-22 06:15:42
When defining what to use for sorting, you do so in the context of the nodes
being sorted - so where you have, in both cases:

        <xsl:sort select="node/rank" data-type="number"  order="ascending"/>

I think you should have

        <xsl:sort select="rank" data-type="number"  order="ascending"/>

With that change I think your code works fine.

David.
--
David McNally            Moody's Investors Service
Software Engineer        99 Church St, NY NY 10007 
David(_dot_)McNally(_at_)Moodys(_dot_)com            (212) 553-7475 

-----Original Message-----
From: Ragulf Pickaxe [mailto:jawxml(_at_)hotmail(_dot_)com] 
Sent: Tuesday, July 22, 2003 4:21 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Sorting and re-ordering down a hierarchy


Hi,

I did not see any response on this (except for one who said 
he used Perl 
instead), so I tried myself.
The templates below, I thought would do what was wanted, but 
I only get it 
to sort on the 1st level, not on the second level. I do not know why.

Does anybody else have a solution, and can anyone tell me why 
my solution 
does not work?

Regards,
Ragulf Pickaxe :)


<xsl:template match="/">
      <output>
      <xsl:apply-templates select="input"/>
      </output>
</xsl:template>

<xsl:template match="input">
      <xsl:apply-templates select="node">
              <xsl:sort select="node/rank" data-type="number" 
order="ascending"/>
      </xsl:apply-templates>
</xsl:template>

<xsl:template match="node">
      <node>
      <xsl:copy-of select="rank"/>
      <xsl:apply-templates select="node">
      <xsl:sort select="node/rank" data-type="number" 
order="ascending"/>
      </xsl:apply-templates>
      </node>
</xsl:template>


<input>
<node>
    <rank>2</rank>
    <node>
        <rank>88</rank>
    </node>
    <node>
        <rank>7</rank>
    </node>
    <node>
        <rank>66</rank>
    </node>
</node>
<node>
    <rank>1</rank>
    <node>
        <rank>3</rank>
    </node>
    <node>
        <rank>2</rank>
    </node>
    <node>
        <rank>1</rank>
    </node>
</node>
</input>

The output I get on this is:
<output>
  <node>
    <rank>1</rank>
    <node>
      <rank>3</rank>
    </node>
    <node>
      <rank>2</rank>
    </node>
    <node>
      <rank>1</rank>
    </node>
    </node>
    <node>
      <rank>2</rank>
    <node>
      <rank>88</rank>
    </node>
    <node>
      <rank>7</rank>
    </node>
    <node>
      <rank>66</rank>
    </node>
  </node>
</output>

_________________________________________________________________
MSN 8 with e-mail virus protection service: 2 months FREE* 
http://join.msn.com/?page=features/virus


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



---------------------------------------

The information contained in this e-mail message, and any attachment thereto, 
is confidential and may not be disclosed without our express permission.  If 
you are not the intended recipient or an employee or agent responsible for 
delivering this message to the intended recipient, you are hereby notified that 
you have received this message in error and that any review, dissemination, 
distribution or copying of this message, or any attachment thereto, in whole or 
in part, is strictly prohibited.  If you have received this message in error, 
please immediately notify us by telephone, fax or e-mail and delete the message 
and all of its attachments.  Thank you.

Every effort is made to keep our network free from viruses.  You should, 
however, review this e-mail message, as well as any attachment thereto, for 
viruses.  We take no responsibility and have no liability for any computer 
virus which may be transferred via this e-mail message.


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list