Sergey Demidenko wrote:
OK, that makes sense. But how do I use the
xsl:variable/xsl:param element to
capture either $order from the menu or $sortByField from the
radio button in
the form?
I recommend this answer from Jeni Tennison:
http://www.biglist.com/lists/xsl-list/archives/200102/msg00277.html
Re: Passing javascript value into xsl
(As for how to get the value out of the menu or radio button, you
probably know more about that part than I do.)
Lars
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list