here is sample xml document, I want to read the value of attribute xmlns.Res
using XSL stylesheet
<?xml version="1.0" ?>
<PT xmlns.Res="PT_MSG">
....
</PT>
here's my stylesheet
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" />
<xsl:template match="HFPT"
xmlns="http://www.w3.org/XML/1998/namespace">
<xsl:copy-of select="@xmlns:Res" />
</xsl:template>
</xsl:stylesheet>
I tried <xsl:copy-of select="@xmlns:Res" />, I got error message -
"Namespace prefix xmlns has not been declared".
So how can I do it in XSL ?
Any solution will be appreciated.
Thanks
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list