Thanks David, Jeni and Martinez,
Thanks for that. All set and correct now.
And am I right in thinking that if the select is "/.." then the test
not($node-set) will return true?
Cheers
Simon
----- Original Message -----
From: "Martinez, Brian" <brian(_dot_)martinez(_at_)cendant(_dot_)com>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Thursday, July 03, 2003 5:50 PM
Subject: RE: [xsl] select in the <xsl:param /> tag
From: Simon Kelly [mailto:kelly(_at_)ipe(_dot_)fzk(_dot_)de]
Sent: Thursday, July 03, 2003 9:10 AM
Subject: [xsl] select in the <xsl:param /> tag
Am I right in saying that declaring the <xsl:param /> tag as
follows will
make the named node set default to null if the template is
called without
the <xsl:with-param /> tag.
<xsl:param name="node-set" select=".." />
This would create a node-set rooted at the parent of the context node, so
it's not null. In fact I don't believe this could ever be null, since all
nodes except the root must have one parent.
or is it
<xsl:param name="node-set" select="" />
This isn't legal XSLT--the select attribute must be non-empty.
cheers,
b.
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