-----Original Message-----
From: Godmar Back [mailto:gback(_at_)stanford(_dot_)edu]
Sent: 02 July 2003 08:51
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] how to test for the element type of the current node
Hi,
what expression do I use if I need to test the type of the
current node
in a for-each loop?
Say I have a DTD that has
<!ELEMENT A (B|C)*>
and I want to write
<xsl:template match="A">
<xsl:for-each select="*">
<xsl:choose>
<xsl:when test="if this node is a B"> <--- this is
what I can't figure out
apply-templates for B
...
<xsl:otherwise>
do something else for C
...
I tried ".=B" inside the test, which doesn't work, I tried just "B",
I tried "boolean(B)", nothing works.
I have rejigged the test a little so we are not talking in terms of yukky dtd's
xslt file
<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
<xsl:template match="test">
<xsl:for-each select="node()">
<xsl:choose>
<xsl:when test="name()='a'">
I have matched an a element
</xsl:when>
<xsl:otherwise>
must be something else
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
xml file
<?xml version="1.0" ?>
<test>
<a>1</a>
<b>2</b>
<c>3</c>
</test>
basically you are testing on the name of the element, so you must use the
name() function...remember that if you are using namespaces ( xmlns ) that u
may have to use local-name(). Also this may not be what you want to do, you may
want to test the node identity, not the name of the node.
well, gl jim fuller
Note that I believe that using <xsl:template match="B"> won't
solve my problem
because I need to do something specific that I only need to if the
B element is nested inside the A element.
This seems such an elementary thing to do (!?), but maybe I
still don't
understand XSL well enough to see an alternative.
Thanks!
- Godmar
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