I would like to count the number of nodes that have an element containing
a
specific element value. Can this be done in XSL?
count(/*/Person[Age = 10])
The above is an XPath expression which, when evaluated returns the wanted
value.
Note, that this XPath expression doesn't rely/know about XSLT -- one could
evaluate it using DOM.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
"Darren Kuik" <darren(_dot_)kuik(_at_)lpl(_dot_)com> wrote in message
news:OPEOKKGGODFCPNLFHGPBOEKPCFAA(_dot_)darren(_dot_)kuik(_at_)lpl(_dot_)com(_dot_)(_dot_)(_dot_)
I would like to count the number of nodes that have an element containing
a
specific element value. Can this be done in XSL? I couldn't find this in
the archive so I apologize if this has been posted before?
Suppose I have an XML file that looks like this:
<Rootnode>
<Person>
<Name>Joe</Name>
<Age>10</Age>
</Person>
<Person>
<Name>John</Name>
<Age>10</Age>
</Person>
<Person>
<Name>Sam</Name>
<Age>18</Age>
</Person>
I want to use XSL to count and display the number of Person nodes that
have
an Age element with value = 10. Is this possible?
Thanks,
Darren
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list