Firstly, the line
<xsl:apply-templates select="descendant::*"/>
looks wrong. This processes the descendants at each level; but at each
level a node is going to process its own children, so this is
unnecessary.
Secondly, you've left something out:
<xsl:apply-templates select>
What was the value of the select attribute?
Finally, I don't see why you need recursion at all. I think the
following should do the job:
<xsl:template match="HEADER">
...
<xsl:apply-templates select="*[(_at_)index]" mode="id"/>
</xsl:template>
<xsl:template match="*" mode="id">
<xsl:copy>
<xsl:copy-of select="@*[not(name()='index')]"/>
<xsl:variable name="p" select="position()"/>
<xsl:copy-of select="/transformation/id_list/id[$p]"/>
<xsl:copy-of select="child::node()"/>
</xsl:copy>
</xsl:template>
But this doesn't copy the elements without an @index attribute. If
that's a requirement, and if they have to be kept in their original
order, then you can't rely on position() in this way. But all is not
lost: instead of position(), use count(preceding::*[(_at_)index])+1.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Volker Witzel
Sent: 27 August 2003 10:14
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] recursion with xsl:apply-templates
Hi,
I have a problem with a recursion and I don't have a clue, why my
solution does not work. I did not find anything on the web,
so your help
is greatly appreciated.
The problem:
I need to perform an XML to XML transformation to augment the
data with
unique keys.
The structure is as follows:
<transformation>
<IRF>
<HEADER>
<REC_IR020_01 index="1">
<UNB_S002_0004>16</UNB_S002_0004>
...
</REC_IR020_01>
<REC_IR030_01 index="1">
<UNH_0062>03081402160553</UNH_0062>
...
</REC_IR030_01>
...
</IRF>
<id_list>
<id>2003-08-25 15:36:59.534096</id>
...
</id_list>
</transformation>
I do not know all tag names, but I know that I have some
elements with
an index attribute, which I need to transform to
<REC_IR020_01>
<id>2003-08-25 15:36:59.534096</id>
<UNB_S002_0004>16</UNB_S002_0004>
...
</REC_IR020_01>
So I have to strip the index attribute and fetch one unique
id from the
id_list for each occurence of an index attribute.
My Solution:
I thought it's startightforward with XSL. My code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xalan="http://xml.apache.org/xslt";>
<xsl:output method="xml" indent="yes" encoding="UTF-8"
omit-xml-declaration="no" xalan:indent-amount="2" />
<xsl:strip-space elements="*"/>
<xsl:template match="/transformation">
<xsl:apply-templates select="IRF"/>
</xsl:template>
<xsl:template match="IRF">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="descendant::*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="node()">
<xsl:param name="idCount" select="1"/>
<xsl:choose>
<xsl:when test="@index">
<xsl:copy>
<xsl:element name="test"><xsl:value-of
select="$idCount"/></xsl:element>
<xsl:call-template name="addIdElement">
<xsl:with-param name="idCount" select="$idCount"/>
</xsl:call-template>
<xsl:apply-templates select>
<xsl:with-param name="idCount" select="$idCount + 1"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:when>
<xsl:otherwise>
<xsl:copy>
<xsl:apply-templates>
<xsl:with-param name="idCount" select="$idCount"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="addIdElement">
<xsl:param name="idCount"/>
<xsl:element name="id">
<xsl:copy-of select="/transformation/id_list/id[$idCount]"/>
</xsl:template>
</xsl:stylesheet>
My problem is that the lines
<xsl:apply-templates select>
<xsl:with-param name="idCount" select="$idCount + 1"/>
</xsl:apply-templates>
do not call the template with the inceremnted parameter, so it always
runs with the default value 1.
Any ideas where my brain is scrumbled?
Volker.
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